660f7401cddae72ae250c1c2

About

very easy crackme. link is here.

basically we just have to find the flag.

Diving in

Open this binary in IDA. in main, sub_7FF78F1A1430 interests us because that is where string is taken as input.

now i could sit and understand how the code is working and generate a script based on that but fuck that shit, debugger supremacy. put a breakpoint on line 26 and step in.

line 108 is very interesting because of memcmp. if we inspect byte_7FF78F1A50B8

we get

{FLG_90TH}

et voilà!